Explain the difference between using the tangent ratio to solve for a missing angle in a right triangle versus using the cotangent ratio. You must use complete sentences and any evidence needed (such as an example) to prove your point of view.

Question

rootbeer003 · Answer

@Hero

Hero · Answer

Suppose we have a right triangle with sides, a, b, c, and acute angles, x and y. |dw:1550779954849:dw|

Hero · Answer

If we want to find the measure of angle x using the tangent ratio it would use $\tan x = \dfrac{b}{a}$ but if we want to find the angle using the cotangent ratio it would be $\cot(x) = \dfrac{a}{b}$. The difference is that the ratios are inverses or reciprocals of each other.

SuicidalSheep32 · Answer

That makes sense but is that all i need to say? I understand what you meant that they are reciprocals but is there anything else that i could put?

Hero · Answer

There's always more that could be said, but in the context of this question, I don't think it's necessary. I think the point of it is to help students realize that the ratios are reciprocals of each other. It's a "Discovery" kind of question.

SuicidalSheep32 · Answer

Ok thank you i have been here not knowing what to put all day and you just cleared it all up thank you so much!

Hero · Answer

You're most welcome.