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Math help pls
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@Shadow
|dw:1551168702520:dw| You know where to put the variables A,B,C, and D, since they tell you which ones are across from each other, A->C, B->D.
We know that AC = c/3 BD = 4 - c
How do you think we can solve this?
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@eviant Let me know
@Shadow 1?
\[\frac{ c }{ 3 } = 4 - c\] \[c = 12 -3c\] \[4c = 12\] \[c = 3\] \[\frac{ c }{ 3 } \rightarrow \frac{ 3 }{ 3 } = 1\] \[4 - c \rightarrow 4 - 3 = 1\] Correct
You can make the diagonals equal to each other since the diagonals are hypotenuses of the same length since they have the same base and same height, given by the rectangle: |dw:1551169640333:dw|
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