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puffer1234:

Analyze the diagram below and complete the instructions that follow. 2004-01-01-03-00_files/i0230005.jpg The measure of 2004-01-01-03-00_files/i0230000.jpg is twice 2004-01-01-03-00_files/i0230001.jpg. If 2004-01-01-03-00_files/i0230002.jpg and 2004-01-01-03-00_files/i0230003.jpg, find 2004-01-01-03-00_files/i0230004.jpg. A. 2004-01-01-03-00_files/i0230006.jpg B. 2004-01-01-03-00_files/i0230007.jpg C. 2004-01-01-03-00_files/i0230008.jpg D. 2004-01-01-03-00_files/i0230009.jpg

dude:

Analyze the diagram below and complete the instructions that follow. i0230005.jpg The measure of m<SUT is twice m<RUS. If m<RUS=(18x-8)º and m<TUS=(4x+16)º, find m<RUT A. 20º B. 30º C. 32º D. 96º

dude:

Alas, finally edited the question

dude:

Anyway TUS and SUT are the same angle So set TUS = 2 times RUS 4x+16=2(18x-8) Solve for x (You should get x=1)

dude:

Now you substitute it back into both equations and add them

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