Math help pls
@Hero
In order to be able to do this you have to be familiar with Pythagorean Theorem and Systems of Equations. But you're probably just wondering how to even start.
What you want to do is start by splitting the highway into two lengths: \(y\) and \(500 - y\) |dw:1552424139384:dw|
From here you apply the pythagorean theorem to the two smaller right triangles to get \(x^2 + y^2 = 300^2\) and \(x^2 + (500 - y)^2 = 400^2\)
We only need to find \(x\)
We can eliminate the y's
ok, you gave 2 equations: x^2+y^2=300^2, and then x^2-(500-y)^2=400^2, which one am I supposed to solve?
You solve both .... SIMULTANEOUSLY (If you've ever heard of that)
confession: I have no idea wth you're saying in order to solve this I'd need to have an x and y, right? what are those?
They are unknown variables. Solving two equations simultaneously is just a fancy way of saying you have to use a system of equations to find the values of x and y.
But before we create the system, we first have to expand \((500 - y)^2\)
Actually, I take that back. We'll have to eliminate the x's then solve for y before we can solve for x.
Sorry, you have to subtract the equation of the smaller triangle from the equation of the bigger triangle. |dw:1552425024058:dw|
After subtracting you get |dw:1552425087620:dw|
400^2-300^2=70000
I don't know if you used a calculator to get that but what I always do is use difference of squares to calculate that. \((400 + 300)(400 - 300)\) = \((700)(100) = 70000\)
so, what do I do now? (and yes, I used a calculator)
NOW, you can expand \((500 - y)^2\)
using what? what is y?
Y is the distance from Blare to the Service station along the highway.
Once we find \(y\) we can easily find \(x\)
how do we find y?
As I said before, the next step is to expand \((500 - y)^2\)
isn't y supposed to be a number?
It's an unknown variable until we solve for it.
(500-y(what am I supposed to subtract?))^2
The 500 - y is squared, meaning you have to do binomial expansion. Remember: \((a - b)^2 = (a - b)(a - b)\)
and \((a - b)(a - b) = a^2 - 2ab + b^2\)
500^2=250000
so, 250000-500-y?
Not quite
250000-2(500-y) + y^2?
How do you figure?
500/300=400/x
Yeah, that's the other way to do it. @dude must have helped you.
which means 3*400/5= 240 no, ( I searched online, found a similar problem, applied it to this)
You were that desperate I suppose.
yes, I seriously was
Good on you
why are you always so bitter?
How does "Good on you" translate to "I'm bitter?".
"you were that desperate, I suppose" , you sound like a 90-year old bachelor whose just annoyed all the time
I have grandparents like that
I'll withhold judgement, except to say, I'm not your grandparents.
There's a subliminal message behind that which implies "Careful not to compare me to your grandparents". You can mis-interpret or mistakenly mis-read someone else's communication style and create unnecessary conflict that way.
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