A sculptor is planning to order a cylinder of composite stone to sculpt a full-sized person. The figure will be 6 feet tall, and 2’ at the longest diameter. The composite stone weighs 50 pounds per cubic foot. About how much will the smallest cylinder weigh that the sculptor can order to make his statue?

Question

Shadow · Answer

If the person is 2ft in wide at their longest diameter, then the cylinder can be no less wide than 2ft, since the cylinder will have to be at least wide enough to do that part, and the rest will be shaped/shaved off.

Now, all you have to do is calculate the volume of the cylinder then multiply it by 50 pounds per cubic foot. They have given you the width, as well as the height (6 ft).

$$V = \pi r^2 h$$

Where,
r = the radius (1 ft)
h = the height (6 ft)
pi = approx 3.14

CheetahGirls · Answer

so 18.84?

CheetahGirls · Answer

so 18.84

Shadow · Answer

I wouldn't round it quite yet. Just multiply what you got by 50.

Shadow · Answer

You get what we're doing though right? We're basically finding the area of this 3D shape, then multiplying it by what each unit (cubic foot) of that material weighs, to get how much the total shape/object weighs.