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Can someone explain this geometry problem to me?
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and this one?
|dw:1553636474270:dw|
applying this logic to your problem QT/TR = QU/US 5/4=x/6 cross-multiplying will give you 7.5
ohh i kept setting it up as 5/4=6/x
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why would the x be the numerator?
similar logic with the other one TQ/TR = QU/US they don't give you US but you can derive it QU + QS = QS 10 + US = 15 therefore US = 5 going back to the original statement TQ/TR = QU/US (x+1)/(x-1) = 10/5 cross-multiplying gives x = 3
oh in that other problem x is the numerator because you're trying to find QU, and QU goes in the numerator of the proportion according to how it's supposed to be set up I just used x instead of QU
oh that makes sense
thank you
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