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Math help please
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apply pythagorean theorem on the left triangle to find the hypotenuse, then apply the pythagorean theorem on the right side of the triangle to find BC remember, a^2 + b^2 = c^2, where a and b are the legs, and c is the hypotenuse
Im still confused
on the left triangle a^2 + b^2 = c^2 since your legs are sqrt(13) and sqrt(23) you can plug these into the equation and find the hypotenuse BC
I get that part of it
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3.60^2+4.79^2 is this what it means
@Valirium can you help me please
leave them in terms of radicals for now [ sqrt(13)]^2 + [ sqrt(23) ] ^2 = c^2 solve for c
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