Find the value of x, rounded to the nearest tenth.

Question

eviant · Answer

https://dlap.gradpoint.com/Resz/~0.VCDjzRpD4g4yUA6.xgQa2kGVWKhrt-6wTwFBtN9vCLKOqD5NhXgvy0ChjpE/7234256,BA/Assets/questions/quiz/geometry/geosincs/geosincs-e-12.png

eviant · Answer

@Vocaloid

Vocaloid · Answer

set up the sin ratio and solve for x

563blackghost · Answer

You need to identify the sides from the angle given.

|dw:1554000299799:dw|

You have your opposite (being x) and your hypotenuse. Now remember SOH, CAH, and TOA which tell you which ratio you would use. In this case you would use Sine since its associates with opposite and hypotenuse.

$\large\bf{sin(x)=\frac{opposite}{hypotenuse}}$

Plug in.

$\large\bf{sin(20)=\frac{x}{18}}$

How would you simplify?

eviant · Answer

@Vocaloid how should I simplify this?

Vocaloid · Answer

she gave you sin(20) = x/18 you just have to solve for x

eviant · Answer

@Vocaloid 6?

Vocaloid · Answer

the question says nearest tenth

x≈6.1564 ---> x = 6.2