i need help with i and j
this is what i did for I
You mis-interpreted B - C which means the elements of B that are not in C
Actually, I take that back. What you've done is almost correct. \(B - C = (3, \infty)\)
oml.. then how would i start it lol
oh wait how come its not bracket for 3?
Because 3 is included in C. We want the elements of B that are NOT in C.
So the next step would be to name the interval \((3, \infty)\) just to make it easier to do the next step.
So let \(D = (3, \infty)\). Now find \(A - D\)
After you find that interval, you'll be done with problem I
BTW, the final result you have is almost correct as well.
so then it would be ( 3 , infinity)?
What did you get for your final final result? Do you remember?
And actually I'm going to say [-5,-3] is correct because B - C does not include 3 but A does. So don't even change your final result.
So funny thing, your intermediary step had a small error, but your final result is still correct.
Looks like you don't need much help with this after all.
i sometimes get confused when to write parenthesis and brackets
Parentheses just means the endpoints of an interval are not included. Brackets mean include the endpoints. Something like that.
so for i got this
What do you mean? We already went over i
@xXMarcelieXx I don't understand what you just wrote. Did you mean, "so far I got this"?
sorry i was working on it lol
for j *
Okay double check your A - B. Remember, A - B means the elements of A excluding the elements of B.
hmm i still dont get it lol
If you can't do j, then explain how you did i
i just did i by doing the number lines though and making sense of it lol
isnt A-B umm ( -5 , 1) ?
Actually, it's [-5,1] which you wrote correctly but when you made your number line, you did it wrong.
when you said " A - B means the elements of A excluding the elements of B " do you mean that we only include the numbers from A that arent in B ?
correct
But do you see where you wrote A - B = [-5,1] which is different from the number line you created for A - B?
oh truee
so then the final answer will change?
It will indeed
hmm would we have union?
oh wait nvm lol so then we would have ( 1 ,3)
You should draw number lines for this one.
You work a lot better by drawing the number lines and posting them here
Okay, so how come you did not graph the number line for (A - B) - C?
oh i graphed it into parts first
but we would get this as a final answer ( A - B ) - C = (1 , 3)
Okay so you have the set for A - B. And then when you excluded all the elements that include C what are you left with?
Aren't there more elements in C than there are in A - B?
yeah there are more elements in C
we would have more numbers in the - infinity and positive numbers right
Do the elements in C INCLUDE the elements in A - B?
@xXMarcelieXx did you die?
oh wait no
im still here lol
Okay
okay so then
So then answer my previous questions
umm they dont right
Go back and look at the number line for C again and ask if the number line for A - B is included.
oh yes it is included
Okay, but aren't you supposed to be excluding everything in C from A - B?
yeah
So basically you already performed A - B. Now you must perform the MINUS C part. In other words, you must remove every element containing C. When you do that, what's left?
@xXMarcelieXx are you still alive?
yes im trying to figure it out but i think its umm 3 , infinity ?
Do you remember the number line for A - B?
State both intervals here for A- B and C
A - B = [ 5 , 1 ] C = (- infinity , 3]
Right and [-5,1] is included in C correct?
yes
But MINUS C means to remove all of C correct?
oh wait i think i made a mistake with this problem for A aaahh
How?
i put A was [ -5, infinity) which was suppose to be [ 5, 4) lol i misread it
Okay.
one sec let me redo it again. sorrry lol
Surprised I didn't catch that myself
im half asleep thats why lol
smh
What course are you taking?
intro too math proofs
I see. Why are you taking intro to math proofs? What is your major?
math teaching and getting a minor in finance
they say its useful for math teaching lool
Good luck in your endeavors
thanks lol i will be back later to finish this stuff
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