What are the solutions to the equation? x2−14x=15 Enter your answers in the boxes. x = ____ and ____
Add 14 to 15 and what do you get?
misty this is not possibile bc. -14 is an x term
Oops. Wrong thing, sorry
like a first step substract from both sides 15
That's for regular equation
Add 14 to both sides right?
It's been a while since i've done these
misty, he's right D:
I know, I meant I was thinking of the way to do regular equations, sorry, I segmented it
Maggie do you understand ?
x^2 -14x -15 = 15-15
Put it in standard form then use quadratic equation
Yeah, I think
no please make what i ve wrote above firstly
bc. after this step you will see that will can factorizing completly what will get
Maggie please collaborate
please continue x^2 -14x -15 = 15 -15
Quadratic formula I meant
not is necessary use the quadratic formula here
Use this formula? x = −b ± √(b2 − 4ac)
x^2 -14x -15 = 0 do you know two numbers with sum equal -14 and product equal -15 ?
It would be 15 and -1, right?
not exactly
15-1 not equal -14
15-1 is +14
yes but you need getting -14 assuming these two numbers
courage Maggie this is easy
-14-1?
-13
misty how is this right ? you need getting -14
I meant -13-1
misty -14-1 = -15not -13
ok but the product need being -15
So -15 and -1?
how ? -15-1 = -16
-13-1=-14
This is so confusing
misty ok but for product you need getting -15
-14-1=-15
product -15 and sum -14
x2−14x=15x2-14 x=15. Move 15 15 to the left side of the equation by subtracting it from both sides.
Alright, just to set some clarity here jhonny is guiding you through factoring, which is an alternative to the quadratic equation You want to find 2 numbers that multiply to -15 and add up to 14 The factors of 15 are (Factors: numbers that multiply to a specific one) 1,15 Now we know one has to be negative since 15 is negative (x-)(x+) Which numbers add up to -14? (one having to be negative) 1 and -15 Hence we should have (x+1)(x-15)=0
Thx u
You should set each factor equal to 0 to find your zeroes \(x\color{red}{\cancel{+1}}=0\) and \(x \color{red}{\cancel{-15}}=0\) \(\color{red}{\cancel{-1}}~~\color{red}{-1}\) \(\color{red}{\cancel{+15}}~~\color{red}{+15}\) Do the opposite of each number, (if it is adding, subtract; likewise if it is subtracting, add) \(x= -1\) and \(x=15\) Am late but was trying to get the latex through :c
Join our real-time social learning platform and learn together with your friends!