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@Vocaloid
C?
yeah
that open circle means composition g is first, that means you need to take the entire f(x) function and plug it into x in the g(x) function, then simplify
Im confused loll
f(x) = 2x - 1 g(x) = x + 2 take f(x) and replace "x" with the g(x) function "x+2" and simplify
D
good
pick two points (for example I see (0,-3) and (3,-4) and apply the slope formula
(y2 -- y1) / (x2 -- x1) (-4-(-3) / (3-0) ?
yeah keep going
-1/3 ?
good, -1/3 is your solution
so you want to repeat the process from before (find the slope) by finding two points on the graph and calculating the slope then after that the equation is y = mx + b where m is the slope and b is the y-intercept
(0,-4) and (0,1) (y2 -- y1) / (x2 -- x1) (1-(-4) / (0-0)
(0,1) is not a point on the graph (you might have been thinking of 1,0)
(0,-4) and (1,0) (1-(-4)) / (0-0)
careful (y2-y1) / (x2-x1) (0 - (-4)) / (1-0)
Yes so that would be 4
good, slope is 4, keep going
y=4x+ idk what the y intercept is
where does the graph cross the y-axis?
-4
?
yeah so y = mx + b becomes y = 4x - 4
now do I solve for y or?
that's it, it wants the equation
again y = mx + b where m is the slope and b is the y-intercept
so do I have to do the same thing I did before?
they give you the slope and intercept in the problem
then after that the equation is y = mx + b where m is the slope and b is the y-intercept y=-1x+5 ?
yeah but we usually write this as y = -x + 5
the 1 is implied
Ohh okay so thats the answer
yes.
first treat the green line as a normal line and write the equation for it then, choose the correct sign (>, <, etc.) based on where the shading is and what type of line (dashed vs solid) it is
How can I determine a equation for a line on a graph again?
please refer to our previous examples pick two points, apply the slope formula, find the y-intercept, then y = mx + b.
start with (1,0) and (0,3) since these are points on the graph
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