Question

calc iii tangent plane problem

Answer 1

@sillybilly123 would you mind taking a look at this when you get a chance? i'm not sure how to get the cartesian equation

Answer 2

The cartesian equation to the plane is obtained as follows

\[x = r \cos \theta \]
\[y= r \sin \theta \]
\[z=r\]
\[x ^{2} + y ^{2} = r ^{2} \cos {^{2}} \theta + r ^{2} \sin ^{2} \theta = r ^{2}\]
\[z ^{2} = r ^{2}\]
The cartesian equation is
\[x ^{2} + y ^{2} = z ^{2}\]

Answer 3

It wants the equation in terms of z so

z = sqrt(x^2+y^2)?

Answer 4

oh that worked

thank you C: