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Mathematics 6 Online
hottpinkkiller:

if m

Shadow:

hello @hottpinkkiller

Shadow:

\[\frac{ Sin C }{ c } = \frac{ Sin A }{ a } \rightarrow \frac{ Sin 90 }{ 29 } = \frac{ Sin A }{ 21 }\] Using the Sin rule, we can create an algebraic equation to solve for A, the angle opposite to side a. Then by subtracting 90 and the measure of angle A, we can get the measure of Angle B and thus use that with the Sin rule to get side B.

Shadow:

This is one avenue, there are others though.

Shadow:

You can also use the Cosine rule after getting the Angle opposite to side b.

Narad:

Apply Pythagoras' theorem \[b=\sqrt {(c^2-a^2)}=\sqrt{29^2-21^2} =20\]

Shadow:

Or that lol.

hottpinkkiller:

thank yall you guys are life savers.

Shadow:

Narad's solution is much easier. C being 90 degrees indicates that this is a right triangle and justifies the use of Pythagoras' Theorem, which makes this much quicker.

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