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Math help please
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@dude will you help me
Ya Do you know the trig ratio for cosine?
ajacent over hypotenuse
18/25
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\(cos(\theta)=\frac{adjacent}{hypotenuse}\) So theta is the angle measure
You're solving for the side, not the angle (we have that)
x/25
yeah, just add the angle \(cos(18)=\frac{x}{25}\) You want to isolate x, do you know how to do that here?
divide it by a number
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D:
What is the opposite of dividing by 25?
multiply
Yeahhh multiply 25 on both sides
cos(18)*25 then x/25*25?
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Yeah but 25 times 1/25 is just 1 so \(25cos(18ยบ)=x\)
23.77
Multiply them into your calculator (doing them by hand is impossible) Make sure to have the mode on degrees if you're using a graphing or an online one
Yeah
Thanks
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