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Mathematics 13 Online
kae:

A small rocket is launched from a height of 6 feet off of the ground at an initial upward velocity of 64 feet per second. Its height is given by the equation h=-16t^2+64t+6 where h is the height of the rocket in feet and t is the time since liftoff in seconds. At what time is the rocket 54 feet in the air?

Vocaloid:

set h = 54 and solve for t either by factoring or using the quadratic formula

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