Question

Rewrite the equation of the circle (x-2)^2+y^2=3 in general form

Answer 1

@dude @Vocaloid @Narad

Answer 2

Do you still need help?

Answer 3

expand (x-2)^2 w/ foil, arrange all the terms in the equation in the order described above

Answer 4

@dude x^2-4x+y^2-5=0??

Answer 5

@Narad

Answer 6

It's the reverse of the 1st question,

Complete the squares
\[x ^{2}+ax+y ^{2}+by+c=0\]
\[x^{2}+ax+a^2/4 +y ^{2}+by+b^2/4=-c+a^2/4+b^2/4\]
\[(x+a/2)^2+(y+b/2)^2=-c+a^2/4+b^2/4\]
If b doesn't exists, then b=0

Answer 7

The -5 is not wright

Answer 8

@Vocaloid I got x^2-4x+y^2+1=0?

Answer 9

Yes