Question

3x^4y^2/4x^2y^4

Answer 1

@Vocaloid

Answer 2

for division, subtract the exponent on top - exponent on bottom

so we can take the coefficients 3 and 4 and set them aside

x^4 / x^2 = x^(_)
y^2 / y^4 = y^(_)
where (top exponent) - (bottom exponent) goes into the blank

Answer 3

x^8/y^16?

Answer 4

subtract, not multiply, the exponents

Answer 5

Frick I'm dumb

Answer 6

x^4 / x^2 ---> 4 - 2
y^2 / y^4 ---> 2-4

Answer 7

x^4 / x^2 = x^(2)
y^2 / y^4 = y^(-2)

Answer 8

x^2/y^-2

Answer 9

good, so putting everything together

3x^2 * (4y^(-2))

when you have a negative exponent you can move the term from the numerator to the denominator

giving us

3x^2 / (4y^2)

Answer 10

Thank you :)