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Write the given expression as a single logarithm.
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\[\ln a + \ln b = \ln(a*b)\] \[b ln (a) = \ln (a^{b})\] use these 2 formulas
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Your answer is correct, but your steps are wrong. \[\ln x + 3\ln y \neq 3 \ln(xy)\] Because: \[3 \ln(xy) = 3 (\ln x + \ln y) = 3\ln x + 3 \ln y\] So you have to put the 3 into the exponent first.
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@Hero can u check?
it looks right tho
Correct
thanks.
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