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Mathematics 17 Online
Ballery1:

Math help

Ballery1:

Write the given expression as a single logarithm.

Ballery1:

|dw:1568234460881:dw|

mhchen:

\[\ln a + \ln b = \ln(a*b)\] \[b ln (a) = \ln (a^{b})\] use these 2 formulas

Ballery1:

|dw:1568242446396:dw|

mhchen:

Your answer is correct, but your steps are wrong. \[\ln x + 3\ln y \neq 3 \ln(xy)\] Because: \[3 \ln(xy) = 3 (\ln x + \ln y) = 3\ln x + 3 \ln y\] So you have to put the 3 into the exponent first.

TheConMan:

|dw:1568251297451:dw|

TheConMan:

@Hero can u check?

Ballery1:

it looks right tho

Hero:

Correct

Ballery1:

thanks.

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