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Mathematics 23 Online
TheConMan:

Math help plz

TheConMan:

I just want someone to check my work. The answer to question 6 is -10 but i’m Getting undefined for some reason plz check. Thanks

TheConMan:

Number 6 plz

mhchen:

Something is not right... You wrote \[\frac{a b}{c} = \frac{a}{c}*\frac{b}{c}\] but eh....

TheConMan:

Omg lol yes thanks

TheConMan:

A+b/ c = a/c + b/c

TheConMan:

Why’s the book saying -10? Did i do something wrong?

TheConMan:

I’m getting -10/0 = undef

mhchen:

You should go from \[\frac{(x+5)(x-5)}{(x+5)} = (x-5) \]

mhchen:

It's only that there's a hole at x = -5. But the limit from the left side and left side go to the same point. |dw:1568418451861:dw|

TheConMan:

|dw:1568418375472:dw|

TheConMan:

Hmm icy.. btw what’s the rule for...wait let me draw

TheConMan:

|dw:1568418536080:dw|

TheConMan:

|dw:1568418591536:dw|

TheConMan:

Did i do something wrong? *~*

mhchen:

Oh I just cancelled them out: |dw:1568418961935:dw| and remind myself that this function is undefined at x = -5.

TheConMan:

Oh icy. I’ll note it down. So there’s a hole at x = -5 and -10. K got it

TheConMan:

So we basically plugged in x= -5 into a y function to see where that hole is... and that hole represents limit. Because the function is undefined at that particular point

TheConMan:

*plugged in x into a y limit*

mhchen:

actually anytime you have something like this: \[f(x)=\frac{(x-a)g(x)}{(x-a)}\] where g(x) can be anything, then f(x) has a "removable discontinuity" at x = a.

TheConMan:

I’ll watch a video on this later. I really gotta finish some questions tonight. Thanks for your help tho. Really appreciated :)

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