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Mathematics 12 Online
TheConMan:

I need math help plz

TheConMan:

What did i do wrong??? Plz only gimme hints. Thanks

TheConMan:

Plz only give me hints. Thanks

mhchen:

Instead of multiplying it by sqrt(x) - 2 try multiply it by sqrt(x) + 2 Since (a - b)(a + b) = a^2 - b^2

TheConMan:

Omg... i think i found the damn mistake... i forgot to change the signs.. /.-

mhchen:

lol

TheConMan:

|dw:1568421709715:dw|

TheConMan:

Brb...let me see if i can solve this solve..

TheConMan:

|dw:1568422057134:dw|

TheConMan:

So far so good?

TheConMan:

And can i take x and 4 common out from both numerator and denominator???

mhchen:

So far so good. No you can't take x and 4 out of the numerator and denominator because they're being added/subtracted not multiplied.

TheConMan:

:/ k i need a hint at this point

mhchen:

|dw:1568422438687:dw|

TheConMan:

Oh my gook... let me distribute the thing brb

TheConMan:

TheConMan:

TheConMan:

Do i need to factor the numerator and denominators?

TheConMan:

|dw:1568423024428:dw|

mhchen:

I think you went off track there... |dw:1568422971796:dw|

TheConMan:

But can i get to the same answer with this tho ? |dw:1568423140859:dw|

mhchen:

no

Hero:

How were you able to cancel out the root in the denominator?

TheConMan:

Omg... i thought they had opposite signs.. /.- good catch bro

TheConMan:

|dw:1568423270490:dw|

TheConMan:

Is it time to plugin the value of x now ?

TheConMan:

I’m gonna invest some time to figure out an easier way to solve these type of questions later..

Hero:

The denominator can be simplified further.

Hero:

Apply FOIL or the distributive property

TheConMan:

Sorry... i made a mistake... i’m Here right now.. |dw:1568423563560:dw|

TheConMan:

Hero.. i’ll Explore that method in a bit mate.. gimme a minute to finish this question bro

TheConMan:

K so do i just plugin the value of x now ?

TheConMan:

Omg... if i plugin x = 4 for x .... i get in trouble

TheConMan:

Wait, let me post a final picture of my solution just so we’re on the right page :)

TheConMan:

TheConMan:

TheConMan:

The answer is 1/4

mhchen:

ye

TheConMan:

But if i plugin 4 for x...i get a 0 in the numerator

Hero:

You haven't finished reducing the denominator

Hero:

or the numerator for that matter

TheConMan:

Wait, really? I’m doing the whole question again to see if i made a mistake and .... anyways.. |dw:1568424380699:dw|

TheConMan:

Do we need to factor the numerator and denominator?

mhchen:

|dw:1568424533266:dw| isn't it obvious

TheConMan:

Omg /.-

Hero:

lol

TheConMan:

Bless your soul for that... cuz i wan’t gonna guess that in 9 eternities..

TheConMan:

|dw:1568424614105:dw|

Hero:

Boom!

TheConMan:

Thank you so much guys.. the next three limit questions are interrelated to one another.. it’s super weird

TheConMan:

Let me take a picture of that thing.. brb

TheConMan:

TheConMan:

It’s from 8,9, and 10

mhchen:

Ah yes

TheConMan:

What do i plugin from question 8 into question 9/?? The answer?

TheConMan:

Why’re questions 8,9 and 10 so similar? Are they high. ?

TheConMan:

What do they mean by (use the results from question 8 and 9?

mhchen:

So here's the definition of a limit: \[\lim_{x \rightarrow a}f(x) = b\] if \[\lim_{x \rightarrow a^{+}}f(x) = b\] and \[\lim_{x \rightarrow a^{-}}f(x) = b\]

TheConMan:

What does that *+* and *-* mean???

mhchen:

+ means from the right - means from the left |dw:1568425082114:dw| In this diagram, the limit at 'a' approaches 'b' from the right, and 'c' from the left

mhchen:

Since 'b' and 'c' do not equal, then the limit at 'a' does not exists.

TheConMan:

Ok let me just do the questions first.. and see if that confirms it

TheConMan:

JSVSL7:

Hey, so you're right on the fact that the limit of x approaching 1 of 3/(x-1) is DNE, but your left hand and right hand limits are wrong. Left hand and right hand limits must be evaluated using logic sometimes. Algaebraically it doesn't always work. The limit of x approaching 1 from the right is infinity, and from the left is negative infinity. For a limit to exist, the right and left hand limits must be the same. Since one is positive infinity and the other is negative infinity, THAT's why it's DNE.

JSVSL7:

Logically, for the limit of x approaching 1 from the right, the denominator keeps getting smaller and smaller. Imagine plugging in 1000, then 100, then 10, then 1.1, then 1.0001. The denominator gets smaller. When that happens, the number is larger, and larger, all the way to infinity! So the answer for that is infinity

JSVSL7:

And from the left, apply the same concept. You're at -1000, then -100, then -10, then -1.1, and -1.000000001. So the number is getting more negative and negative...toward negative infinity. So the limit of x approaching 1 from the left is negative infinity.

mhchen:

He's right. Take a look at the graph: https://www.desmos.com/calculator/dw4lsng8ej

TheConMan:

I got it. Thanks pal.

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