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Mathematics 15 Online
Ballery1:

need math help plz

Ballery1:

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Ballery1:

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Ballery1:

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JSVSL7:

So once again, use logic here. Seems tough but it really isn't. Find LHS and RHS. For LHS, first think you're at x=-1000 then -100 then -10 and then - 0.0001. You are approaching 0. Same for RHS,, first 1000 then 100 then 10 then 0.000001. It's approaching 0 again.

JSVSL7:

Since the RHS and LHS are approaching the same number, 0, the limit of x approaching 0 is..

Ballery1:

0

JSVSL7:

That's the answer

Ballery1:

but wait...

JSVSL7:

?

Ballery1:

u see that 2 in the piecewise func??? what do we do with that?

JSVSL7:

Nothing. Try graphing the function and you'll understand it better

Ballery1:

that's what's throwing me off

JSVSL7:

Okay there's another more algebraic way as well

Ballery1:

it's just an integer... so do i just draw a dot ??? but where ? on the x or y ?

JSVSL7:

The limit of x approaching a for any absolute value can be broken down (theorem) x for x>= a -(x) for x<=a

JSVSL7:

So break it down here. Just because there is a do not equal sign doesn't mean you can't apply the limit

JSVSL7:

Recall, a function may not be defined at one point, but it still may have a limit

Ballery1:

yes

Ballery1:

but i wanna know how do we deal with that 2 tho ?

Ballery1:

how do i graph that thingy?

JSVSL7:

Do you know how to graph a piece wise?

Ballery1:

bro i just did...in the last quesiton

JSVSL7:

So then you can graph here it just like you did. 2 is defined over x=0, so it's just a point.

Ballery1:

AAhh thats what i was thinking but will it be over the x or y tho?

Ballery1:

will it be on the horizontal x-axis or vertical y-axis?

Ballery1:

omg... stupid me.... /.- i got it

Ballery1:

k thanks for the help mate... let me finish these two questions and then i'mma start a new exercise... it's about solving for limits... the fun stuff

Ballery1:

thanks love :)

JSVSL7:

......

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