Ask your own question, for FREE!
Mathematics 19 Online
Ballery1:

i need math help

Ballery1:

expand and simplify the expressions.|dw:1568750975453:dw|

Ballery1:

|dw:1568751029373:dw|

Ballery1:

|dw:1568751086698:dw|

Ballery1:

i need a hint here.

payload:

what is ln1?

mhchen:

|dw:1568751300203:dw| \[\ln(x^{a})=a \ln(x)\]

payload:

correct ^

Ballery1:

|dw:1568751358097:dw|

Ballery1:

i need another hint here

mhchen:

\[ax + bx = (a+b)x\]

Ballery1:

|dw:1568751523440:dw|

Ballery1:

|dw:1568751642218:dw|

Ballery1:

|dw:1568751748991:dw|

Ballery1:

is this it?

mhchen:

Yeah, I think that's the most simplified form.

Ballery1:

ight mate. i think i have one more log related question. brb

Ballery1:

i wanna ask you a quick question...

Ballery1:

so for this question... |dw:1568756109014:dw|

Ballery1:

|dw:1568756133097:dw|

Hero:

Your previous log needs work

Hero:

The original expression you were working on that is

Ballery1:

|dw:1568756199485:dw|

Hero:

I'd have to see all the steps you did for the incorrect one

Hero:

Really, what you should do is post a new question for each different question to avoid confusion.

Ballery1:

kkk

mhchen:

|dw:1568758816962:dw|

mhchen:

\[\ln(1+a^{x}) \neq x \ln(1+a)\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!