Ballery1:
i need math help
Ballery1:
expand and simplify the expressions.|dw:1568750975453:dw|
Ballery1:
|dw:1568751029373:dw|
Ballery1:
|dw:1568751086698:dw|
Ballery1:
i need a hint here.
payload:
what is ln1?
mhchen:
|dw:1568751300203:dw| \[\ln(x^{a})=a \ln(x)\]
payload:
correct ^
Ballery1:
|dw:1568751358097:dw|
Ballery1:
i need another hint here
mhchen:
\[ax + bx = (a+b)x\]
Ballery1:
|dw:1568751523440:dw|
Ballery1:
|dw:1568751642218:dw|
Ballery1:
|dw:1568751748991:dw|
Ballery1:
is this it?
mhchen:
Yeah, I think that's the most simplified form.
Ballery1:
ight mate. i think i have one more log related question. brb
Ballery1:
i wanna ask you a quick question...
Ballery1:
so for this question... |dw:1568756109014:dw|
Ballery1:
|dw:1568756133097:dw|
Hero:
Your previous log needs work
Hero:
The original expression you were working on that is
Ballery1:
|dw:1568756199485:dw|
Hero:
I'd have to see all the steps you did for the incorrect one
Hero:
Really, what you should do is post a new question for each different question to avoid confusion.
Ballery1:
kkk
mhchen:
|dw:1568758816962:dw|
mhchen:
\[\ln(1+a^{x}) \neq x \ln(1+a)\]
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