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Mathematics 8 Online
Ballery1:

math hep plz :)

Ballery1:

Show that there's at least one solution of the equation \[x^2 = x+1\] in the interval of (0,2).

JSVSL7:

aik menut

Ballery1:

take ur time bhai :)

Ballery1:

\[x^2 - x-1 = 0\]

JSVSL7:

Just use quadratic formula

Ballery1:

i think i got it.

JSVSL7:

ok

Ballery1:

i'll post the answer in a bit :)

Ballery1:

i've completed the questions but i need to eat something before i pass out. please gimme 20 minutes. i'll upload the answers. God Bless!!! :)

Ballery1:

JSVSL7:

When it asks for a solution it means root so it's asking when f(x)=0 not what is f(0)

JSVSL7:

Use quadratic formula for #1

Ballery1:

there's no answers for these two questions in the back of my tb

Ballery1:

i've literally done those questions exactly how they did it in the tb

JSVSL7:

When it says solution it doesn't mean answer it means x-intercept or root. But there is an even better way to explain instead of finding the x-intercept if it is allowed. Use the Intermediate Value Theorem

JSVSL7:

Have you touched on limits yet?

Ballery1:

thats whats am using

Ballery1:

this chapter is about limits

JSVSL7:

Ignore what I said earlier, they're both right :). You used IVT correctly

Ballery1:

okie dokie...thanks bhai :)

JSVSL7:

Koi baat nahi bhai

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