math hep plz :)
Show that there's at least one solution of the equation \[x^2 = x+1\] in the interval of (0,2).
aik menut
take ur time bhai :)
\[x^2 - x-1 = 0\]
Just use quadratic formula
i think i got it.
ok
i'll post the answer in a bit :)
i've completed the questions but i need to eat something before i pass out. please gimme 20 minutes. i'll upload the answers. God Bless!!! :)
When it asks for a solution it means root so it's asking when f(x)=0 not what is f(0)
Use quadratic formula for #1
there's no answers for these two questions in the back of my tb
i've literally done those questions exactly how they did it in the tb
When it says solution it doesn't mean answer it means x-intercept or root. But there is an even better way to explain instead of finding the x-intercept if it is allowed. Use the Intermediate Value Theorem
Have you touched on limits yet?
thats whats am using
this chapter is about limits
Ignore what I said earlier, they're both right :). You used IVT correctly
okie dokie...thanks bhai :)
Koi baat nahi bhai
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