differentiate the function y = 1/x. Express the derivative using Leibniz notation
@JSVSL7 please help :)
do i replace the x from F(x+h)-F(x)/h with 1/x?
what do you mean by "how did you call for me"? sorry, i don't get it
so this is what i mean ...one second.
f(x+h)-f(x)/h = f(1/4+h)-f(1/4)all over h
correct me if i'm wrong... the first derivative represents the avg speed, the second derivative represents the acceleration and what does the third derivative rep?
oh i thought the 3rd derivative might mean something ...hmm anyways. thanks
Then y = x √ x − 4 √ x = x 3 2 − 4 x 1 2 Differentiate using the power rule. d y d x = ( 3 2 ) x 1 2 − 2 x − 1 2 = ( 3 2 ) x 1 2 − 2 x 1 2 = ( 3 √ x 2 ) − 2 √ x Get a common denominator of 2 √ x , and you'll arrive at their answer.
there
I just learned this in advanced
did I do it right?
The definition of the deivative of a function f(x) according to Leibniz is \[f'(x)=\lim _{h \rightarrow 0} \frac{ f(x+h) -f(x)}{ _{} h}\] Here \[f(x)= 1/x\] You can continue.......
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