In a monohybrid cross, if the gene for tall (T) plants was incompletely dominant over the gene for short (t) plants, what would be the predicted result of crossing two intermediate (Tt) parent plants? (Hint: You may want to complete a Punnett square.) 25 percent tall, 50 percent intermediate, 25 percent short 50 percent tall, 25 percent intermediate, 25 percent short 100 percent intermediate 25 percent tall, 75 percent intermediate
There is no need to do a punnett square unless you want to visualize it. Since you're doing a heterozygous monohybrid cross, the genotypic ratio is always 1:2:1 and the phenotypic ratio is always 3:1. However, it is given that the heterozygous pair yields a different phenotype, suggesting that there is incomplete/codominance. So by 1:2:1 of a phenotypic ratio, it is A.
Thank you! Can you help me with some more?
Sure.
Should I make a different post or add it to this?
Whatever you wish
Ok imma add it to this
This pedigree chart tracks the inheritance of a recessive trait that is not sex-linked. Based on the information in the chart, which of the following statements is true about individuals 3 and 4?
A - This is partially correct. If only 1 was heterozygous, then the female wouldn't have been impacted. B- No because if they were both homozygous recessive then they would have the trait in observance. C - This is correct. This is the only way the daughter would be impacted. D- No, otherwise it would've shaded it in.
I assume you take FLVS, based on the formatting?
:D yah
Do you think you have time for a few more?? If not its fine
Sure
What are the genotypes of the parents in the monohybrid cross below if the following offspring genotypes are predicted? Tt and Tt TT and tt Tt and TT Tt and tt
I don't know how to explain this - it's pretty straightforward. It should be a cross between a homozygous dominant and a heterozygous. Option C
Ok...thanks 2 more questions
k
Which of the following genotypes is homozygous recessive? ss Bb TT XY
Recessive - denoted with lower case abbreviation of the allele Homozygous - 2 copies So it's A
Thanks 1 more question The allele for a widow’s peak has complete dominance over the allele for a straight hairline (w). What is the probability of two parents heterozygous for a widow’s peak (Ww) having an offspring with a widow’s peak? 75 percent 50 percent 0 percent 25 percent
It's not 50%...I know that
So it's a heterozygous monohybrid cross. The set genotypic ratio is always 1:2:1 and the phenotypic is 3:1. It's clearly A.
THANK YOU! I gotta go..imma close this post
Have a great rest of the day!
You too
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