Given the equation square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution.
8x+1=5 You would have to subtract 1 from both sides, getting 8x=4 Then you would divide both sides by 8 Which means X=?
Welcome to QuestionCove cx
whats the answer?
I can't directly give you the answer because then you won't learn To find the value of x all that is left for you to do is divide 4 by 8
it cant be two
No, because 8 divided by 4 is 2 You are supposed to do 4 divided by 8
x = one fourth, solution is not extraneous x = one fourth, solution is extraneous x = 3, solution is not extraneous x = 3, solution is extraneous
it has to be one of these
angel it's the square of "8x+1"
\[\sqrt{8x+1}=5\] like this :=))
square root ** of "8x+1"
OH
My apologies @iamchris08
no youre good
Nnesha you wanna take this one?
you can continue..
You would square both sides, getting 8x+1=25 Then subtract the 1 from both sides getting 8x=24 So x=?
3
Then do (Square root) 8*3+1=5 Simplifying it to get 5=5 showing thay 3 is your answer c:
thx
Join our real-time social learning platform and learn together with your friends!