Question

Given that ∠XQR = 180° and ∠LQM = 180°, which equation could be used to solve problems involving the relationships between ∠XQM and ∠RQM?

A)180 + (3a + 39) = (136 − 2a)

B)(3a + 39) − 180 = (136 − 2a)

C)(136 − 2a) − (3a + 39) = 180

D)(136 − 2a) + (3a + 39) = 180

E)360 − (3a + 39) = (136 − 2a)

Answer 1

i believe it would be B

Answer 2

No. Two angles that make up a line when added equal 18 degrees.

Answer 3

they are called supplementary angles.

Answer 4

hmmm

Answer 5

Angle XQM = Angle RQM = 180

Answer 6

it's D

Answer 7

correct. GOOD JOB.

Answer 8

I mean technically you would want to subtract 1 of the equation from 180 degrees, but thats not an option

Answer 9

OK THANK YOU FOR THAT TIP, BUT I UNDERSTAND WHAT YOU MEANT BY IT

Answer 10

or could've done it like

(136 − 2a) + (3a + 39) = 180

Supplementary angles add to 180°