Question

A marine biologist is studying the growth of a particular species of fish. She writes the following equation to show the length of the fish, f(m), in cm, after m months:

f(m) = 3(1.09)m

Part A: When the marine biologist concluded her study, the length of the fish was approximately 5.98 cm. What is a reasonable domain to plot the growth function? (4 points)
I believe the answer is 0 < x < 9

Part B: What does the y-intercept of the graph of the function f(m) represent? (2 points)
The y-intercept (3) represents how big the fish was when she first started her study (at 0 months).

Part C: What is the average rate of change of the function f(m) from m = 2 to m = 8, and what does it represent? (4 points)
idk

Answer 1

@Gdeinward

Answer 2

I believe I have everything correct but idk for part c..im working on it.

Answer 3

so does f(m) = 3(1.09)m have any exponents?

Answer 4

f(m)=3(1.09)^m

Answer 5

I think the average rate of change is 0.309.....I think

Answer 6

Is that correct?

Answer 7

well to find ARC, you divide y1 - y2 / x1 - x2

Answer 8

so ehen m equals 2, m is the x variable, and your resulting number after you solve the equation is your y variable

Answer 9

so solve f(m) = 3(1.09)^2 to find ur y
then solve f(m) = 3(1.09)^8 to find your second y

Answer 10

DO you understand?

Answer 11

So 0.309?

Answer 12

:P I think it is 0.309! i DO undertand

Answer 13

oof.

Answer 14

eh I hadnt done the math, give me a sec

Answer 15

Ok

Answer 16

I got 0.6475145

Answer 17

hm

Answer 18

How did u do it?

Answer 19

I used the formula in my school

Answer 20

\[\frac{ 3-4.235}{ 0-4}\]

Answer 21

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Gdeinward
so solve f(m) = 3(1.09)^2 to find ur y
then solve f(m) = 3(1.09)^8 to find your second y
\(\color{#0cbb34}{\text{End of Quote}}\)
I solved the above equations to get
f(m) = 3(1.09)^2 = f(m) = 3.885087
f(m) = 3(1.09)^8 = f(m) = 5.97768792507

Answer 22

then I subtracted answer a from answer B to get 2.09260792507

Answer 23

f(b)−f(a) over b−a