The domain for f(x) and g(x) is all real numbers. Let f(x) = 4x-1 and g(x) = x2-5x + 3 Find (fg)(x).
@Nnesha using FOIL, I got 4x^2+12x-x^2-3
4x^3+12x-x^2-3
but Mathway says the answer is 4x^3-21x^2+17x-3
could you tell me what I'm doing wrong?
I can't without any work shown.
what did you get after distribution(before simplifying )?
my guess is you forgot to multiply "all g(x) terms" with 4x
(4x)(x^2)=4x^3 (4x)(3)=12x (-1)(x^2)=-x^2 (-1)(3)=-3 Put it all together, and the answer is:4x^3+12x-x^2-3
left `-5x` alone?
|dw:1573107725095:dw|
oh, sorry about that so, 2. should've been (4x)(x^2-5x)?
or (4x)(5)=-20+x^2=21x^2
-21x^2
\[\color{blue}{4x-1}(x^2-5x+3)\]\[\color{blue}{4x}(x^2-5x+3)\color{blue}{-1}(x^2-5x+3)\]
how did you get -21? what number did you add/subtract?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @eviant or (4x)(5)=-20+x^2=21x^2 \(\color{#0cbb34}{\text{End of Quote}}\) something is missing ? 1st) you can't combine 20(constant) with x^2 2nd) -20+1 isn't -21
ugh, sorry, I suck at this stuff, what am I supposed to do instead?
I feel like you know how to do this stuff. But you need to start writing it out to prevent mistakes
|dw:1573108312655:dw| write like this draw arrows make sure to pay attention to the negative sign
|dw:1573108360676:dw|
once you done with the first term distribute the 2nd term like that
1. 4x^3 2. -20x^2 3. 12x
that's correct!
|dw:1573108517357:dw| try this one
1. -x^2 2. 5x 3. -3
awesome now we have to combine like terms here is what we have `4x^3-20x^2+12x-x^2+5x-3`
uh, so -20x^2-x^2=-21x^2?
and, 12x+5x=17x?
@Nnesha is this correct so far?
yes!
so, 4x^3-21x^2+17x-3?
yes. that's it!
good work1 o^_^o
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