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If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower? Given: g = –9.8 meters/second2
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You know the kinematic equation \[x = x_{0} + vt + \frac{1}{2}at^{2}\] right? We can plug in the numbers: \[x = 0 + (0)(3.5) + \frac{1}{2}(9.8)(3.5)^{2}\]
thc
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