1. Circle the following E. coli genotypes that will metabolize lactose if lactose is present in the culture media. 5 marks total a) I^+ P^ – O ^+ Z^ + Y^+ A^+ b) I^s P^+ O^+ Z^+ Y^+ A^+ c) I^– P^+ O^+ Z^+ Y^+ A^+ d) I^s P^+ O^c Z^+ Y^– A^+ e) I^+ P^+O^c Z^– Y^+ A^+
@Vocaloid
When lactose is present, allolactose will bind to the repressor preventing it from attaching to the operator. Thus, RNA will be able to bind to the promoter and gene will be expressed.
allolactose works as an inducer.
Z,Y,A are the genes whereas + means expressed - means no transcription occurred O is operator, + means it is normal. Oc represents a constitutive operator which doesn't allow repressor to bind so doesn't matter if the lactose is present or not when there is Oc genes will be expressed.
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