For ΔABC, ∠A = 8x - 10, ∠B = 10x - 40, and ∠C = 3x 20. If ΔABC undergoes a dilation by a scale factor of
1
2
to create ΔA'B'C' with ∠A' = 6x 10, ∠B' = 70 - x, and ∠C' =
10x
2
, which confirms that ΔABC∼ΔA'B'C by the AA criterion?

Question

For ΔABC, ∠A = 8x - 10, ∠B = 10x - 40, and ∠C = 3x 20. If ΔABC undergoes a dilation by a scale factor of 
1
2
 to create ΔA'B'C' with ∠A' = 6x 10, ∠B' = 70 - x, and ∠C' = 
10x
2
, which confirms that ΔABC∼ΔA'B'C by the AA criterion?

russkaya05 · Answer

I think its C.
C) ∠B = ∠B' = 33° and ∠C = ∠C' = 80°
basically the triangle has a total of 180 degrees.
In order to get the x:
180 = 4x + 7 + 2x + 3 + 6x -10
180 = 12x - 0 
x = 15
∠A = 4x + 7 = 67
∠B = 2x + 3 = 33
∠C = 6x - 10 = 80

hopefully this is what you were looking for