bill533:
There are six numbers on a normal die. What is the probability that you roll a 5 or a 6?
Nnesha:
\[\rm P( A ~~or~~B)=P(A) +P(B)-P(A ~and~B)\] A and B represent the events. In this case either you will get 5 or 6. Since the Event A and B are disjoint P( A and B) will be 0. Event A and B cannot occur at the same time. you can't get 5 and 6 at the same time.
Nnesha:
P(A)= what is the possibility of getting 5? P(B)= what is the possibility of getting 6?
Babyplier:
Sorry about my answer. I actually came here to delete it, but thx for doing it for me!
GoldenDance:
oh no problem
Nnesha:
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Nnesha P(A)= what is the possibility of getting 5? P(B)= what is the possibility of getting 6? \(\color{#0cbb34}{\text{End of Quote}}\) ** P(5)= what is the possibility of getting 5? P(6)= what is the possibility of getting 6?
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