Question

a ball is thrown from a height of 47 meters with an initial downward velocity of 4 m/s. The ball's height h (in meters) after t seconds is given by the following. How long after the ball is thrown does it hit the ground?

Answer 1

h=47-4t-5t^2

Answer 2

Use your kinematics equations

\(Δd=d_0 + vt + \frac{1}{2}at^2\)

Answer 3

?

Answer 4

Solve for t using quadratic formula

Answer 5

i am really struggling with this

Answer 6

are there multiple choice answers?

Answer 7

no

Answer 8

hmm okay give me a sec

Answer 9

TY

Answer 10

Okay do you need to show your work for the answer?

Answer 11

NO

Answer 12

okay so i think im right but the easiest way to do this is to put h=47-4t-5t^2 in desmos and since time cant be negative it will be the x-intercept

Answer 13

do you know what desmos is?

Answer 14

NO

Answer 15

okay desmos is a graphing website that graphs almost everything for you instantly

Answer 16

ill send a screenshot

Answer 17

TY

Answer 18

so when I typed in the equation on the side it gave me when it will hit and it should be 2.692

Answer 19

so when it hits the ground it will have taken it 2.692 s

Answer 20

hope this helps!

Answer 21

thank you so much!!!!!

Answer 22

no problem:)