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a ball is thrown an initial height of 1 meter with an initial upward velocity of 5 m/s. The ball's height h (in meters) after t seconds
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use your kinematics equations to make a function between y & t. \(y_o\)=1 m \(v_{yi}\)=5m/s \(a\)=-9.8m/s^2
You would use this one \(Δy=v_ot+\frac{1}{2}at^2\) apply it \(y=5t+\frac{1}{2}(-9.81)t^2\) If you are given a diff acceleration other than gravity then use that
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