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The index of refraction of a substance is 1.5. Find the sine of the angle of refraction if the sine of the angle of incidence is 0.15
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because i need help on this question i do not understand it
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np
snell's law n1 * sin(theta 1) = n2 * sin(theta 2) where n1 and theta 1 refer to the incident beam, and n2 and theta 2 refer to the refracted beam n1 is given 1.5, sin(theta 1) is given as 0.15. n2 is presumed to be air (n2 = 1). therefore all that's left is to solve for sin(theta 2)
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