Question

how do you put this equation into standard exponential form
3 (5)^(2x-3)

Answer 1

are they looking for something like a(b)^x

in that case, you need to apply exponent rules to isolate x. you can start by separating 5^(2x-3) into 5^(2x) / 5^3 and then 5^(2x) into 5^2 * 5^x

Answer 2

yes

Answer 3

so how would the final equation look like?

Answer 4

once you have 5^x isolated you just write everything you took out in front of the 5^x

3 (5)^(2x-3) ---> [3*5^(2) / (5^3)]* (5)^(x)

simplify everything inside the parentheses

Answer 5

*inside the brackets

Answer 6

eh hold on I made a mistake

5^(2x) ---> (5^2)^x

but everything else is ok

Answer 7

wow, ty