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Which equation has no solution? 4(x + 3) + 2x = 6(x + 2) 5 + 2(3 + 2x) = x + 3(x + 1) 5(x + 3) + x = 4(x + 3) + 3 4 + 6(2 + x) = 2(3x + 8)
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what you can do for this is to disribute and solve for the x's. The eqn with no solution will be the one where the x's cancel out and some number is going to be equal to some other number
for instance, 3 doesn't equal 0 so if one of your eqns are like this then that is the correct answer
r u set?
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