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suppose a normal distribution has a mean of 222 and a standard deviation of 16. what is the probability that the data value is between 174 and 238 round your answer to the nearest 10th of a percent
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Do you use a calculator or a z-table? First you find the z score by doing: (174 - mean) / standard_deviation (238 - mean) / standard_deviation Find their probabilities |dw:1583247820042:dw| And subtract the 174 probability from the 238 probability
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