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Help with sqrt y = 8sqrt2
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Is it \(\sqrt{y} = 8\sqrt{2}\)
@zarkam21
You can begin by squaring both sides.
So we are left with y = 8sqrt2^2
If you square both sides you get \((\sqrt{y})^2 = (8\sqrt{2})^2\) Then you have to apply the property \((ab)^2 = a^2b^2\) on the RHS to get \(y = 8^2(\sqrt{2})^2 \)
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Y=128
8^2=64 *2
y does equal 128 but \(8^2 \ne 64*2\)
Squaring stuff often involves throwing away information. So: \(\sqrt{y} = 8 \sqrt2 = \sqrt{64} \sqrt{2} = \sqrt{64 \times2} = \sqrt{128}\)
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