Question

a 20.0 Ohm and 60.0 Ohm resistor are connected in series to a 9.00 V battery. what is the voltage drop across the 20.0 Ohm resistor?
(Hint: how much current flows across it?)(unit=v)

Answer 1

Hi, you must use Ohm's law
\(V=IR\)
wherein V=voltage, I=current, and R=resistance

Since this is a series, you must find the total resistance
\(R_{eq}=\sum~R_n=R_1+R_2+R_3...\)
Once you find the total resistance plug it into V=IR