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jennylove:
How much current does a 300.0 kW device draw when 120 V is placed across it? 3.6×10^4 A 2.5×10^0 A 4.0×10^−2 A 2.5 × 10³ A D ?
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jennylove:
@TheSmartOne
TheSmartOne:
P = IV and that's what I got too! Good job!!
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