Question

A swimming pool is 50 meters long and 25 meters wide. The adjustable bottom of the pool can be up to 3 meters deep for
competition and as shallow as 0.3 meter deep for recreation. The pool was filled to the recreational level, and then the floor was
lowered to the competition level. If the volume of a liter of water is 0.001 cubic meters, how much water had to be added to fill the
pool?

Answer 1

Could u please give me an answer

Answer 2

thanks for helping

Answer 3

so you need calcule the volume of the pool for these two cases ,in case of recreational level and in case of competition level

Answer 4

i dont understand what u said

Answer 5

i really need some help

Answer 6

i just need a answer

Answer 7

@Hero @eiwoh2 @Isry @silvernight269 @Vocaloid See if you can help this user please :)

Answer 8

We can't get direct answers

Answer 9

Is this pool rectangular?

Answer 10

@pauljohn

Answer 11

Think of it as if a diagonal cut was made in a rectangle prism.

Answer 12

@pauljohn

Answer 13

Assuming the pool is rectangular, you need to solve for the volume of the pool:

Start with:
V = 50 * 25 * 3 = 3750m^3

You mentioned that 1liter = 0.001m^3

1000 liters would be equivalent to 1m^3.

1000 liters/1m^3  = x liters/3750m^3

1x = 3,750,000 liters

Using the formula for volume, we can decipher that the answer and volume of the pool is 3,750,000 liters :)

Answer 14

Pinky, thats wrong.

Answer 15

Is it?

Answer 16

It cus the pool floor starts rly shallow. meaning its only 0.3 m deep.

Answer 17

Ah, I must've read it wrong

Answer 18

Then at the end of the pool its the deepest so its 3 m