Complete the equation so it has infinitely many solutions. 4x + 7 = 4(x + 3) –
help
To have an infinite number of solutions in this equation, we must solve for x and reach a point where we have "0x = 0."
ok
what do we do first
The missing term which we will call it 'y' is in the equation 4x + 7 = 4(x + 3) – y
Next you have to distribute 4 over the parentheses on right side 4x + 7 = 4x + 12 – y
Then substract 7 on both sides 4x + 7 - 7 = 4x + 12 – y - 7 4x = 4x + 5 – y
You now have minus 4x on both sides
4x - 4x = 4x + 5 – y - 4x
tell me what you get now
cancel out all the 4x terms and you will get it
@lizzie777 Are you there?
yes
is it 5
No, cancel out all the 4x terms in this equation and tell me what you are left with 4x - 4x = 4x + 5 – y - 4x
5 – y
Correct
so the missing piece is 0
wait no sorry
5 I mean
0x = 5 - y the equation will have infinitely many solutions if the right side is 0 5 - y = 0 5 = y
the answer is 5
Yes.
thanks
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