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lizzie777:
Complete the equation so it has infinitely many solutions.
4x + 7 = 4(x + 3) –
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lizzie777:
help
justus:
To have an infinite number of solutions in this equation, we must solve for x and reach a point where we have "0x = 0."
lizzie777:
ok
lizzie777:
what do we do first
justus:
The missing term which we will call it 'y' is in the equation
4x + 7 = 4(x + 3) – y
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justus:
Next you have to distribute 4 over the parentheses on right side
4x + 7 = 4x + 12 – y
justus:
Then substract 7 on both sides
4x + 7 - 7 = 4x + 12 – y - 7
4x = 4x + 5 – y
justus:
You now have minus 4x on both sides
justus:
4x - 4x = 4x + 5 – y - 4x
justus:
tell me what you get now
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justus:
cancel out all the 4x terms and you will get it
justus:
@lizzie777 Are you there?
lizzie777:
yes
lizzie777:
is it 5
justus:
No, cancel out all the 4x terms in this equation and tell me what you are left with
4x - 4x = 4x + 5 – y - 4x
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lizzie777:
5 – y
justus:
Correct
lizzie777:
so the missing piece is 0
lizzie777:
wait no sorry
lizzie777:
5 I mean
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justus:
0x = 5 - y
the equation will have infinitely many solutions if the right side is 0
5 - y = 0
5 = y
lizzie777:
the answer is 5
justus:
Yes.
lizzie777:
thanks
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