The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling tower is the same as the center of the hyperbola, and the x-axis represents the ground surface.

The diameter at the center of the tower is
meters. The center of the tower is
meters above the ground.

Question

The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling tower is the same as the center of the hyperbola, and the x-axis represents the ground surface.

The diameter at the center of the tower is 
meters. The center of the tower is 
meters above the ground.

imqwerty · Answer

you just have to convert the given equation into standard form