The average weight of two boys is 48 kg. If one boy is 6 kg heavier than the other, find the height of the heavier boy.
we know that there are 2 boys and their average is 48. based off this info, since there are 2 boys, we can work backwards. 48*2=96
what two numbers add up to 96 but have a difference of 6?
i did 48*2 because with averages, since there are two boys, we would originally divide by 2 to find the average of the two numbers. we need the number that would divide by 2 and end up being 48. thats where 96 comes in.
You could do it the way @ramen told you or you could use a more prescriptive method: Let us denote the weight of the first boy as x, and second by as y. \[W_{ave}=\frac{x+y}{2}\] \[∴ 1)...\frac{x+y}{2}=48~kg\] You are also given that one boy is 6 kg heavier than the other (i.e., x is 6 kg heavier than y). \[2)...x=6+y\] Now you can employ substitution to find the values of x and y, and your answer would be the weight (I believe the question saying 'height' is an error) of the heavier boy (i.e., weight of x)
how tall is the bigger boi tho
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