Question

Is there a way to create a variable as the name of the turtle in Python so that I can make the design a function?

Answer 1

@dude

Answer 2

Nah I don't think so.

Answer 3

tbh I don't even know

Answer 4

figured it out.

Answer 5

import turtle

def tree(turtle):
turtle.begin_fill()
turtle.speed(100)
turtle.right(45)
turtle.forward(71)
turtle.right(135)
for i in range(2):
turtle.forward(25)
turtle.left(135)
turtle.forward(71)
turtle.right(135)
turtle.forward(200)
for i in range(2):
turtle.right(135)
turtle.forward(71)
turtle.left(135)
turtle.forward(25)
turtle.right(135)
turtle.forward(71)
turtle.end_fill()
turtle.penup()
turtle.right(135)
turtle.forward(150)
turtle.color("brown")
turtle.pendown()
turtle.begin_fill()
turtle.left(90)
turtle.forward(25)
turtle.right(90)
turtle.forward(75)
turtle.right(90)
turtle.forward(50)
turtle.right(90)
turtle.forward(75)
turtle.right(90)
turtle.forward(25)
turtle.end_fill()

def main():
jack = turtle.Turtle()
jack.hideturtle()
jack.color("green")
jack.penup()
jack.setposition(0, 75)
jack.pendown()
tree(jack)
pack = turtle.Turtle()
pack.hideturtle()
pack.color("yellow")
pack.penup()
pack.setposition(200, 0)
pack.pendown()
tree(pack)
tack = turtle.Turtle()
tack.hideturtle()
tack.color("red")
tack.penup()
tack.setposition(123, 225)
pack.pendown()
tree(tack)
sack = turtle.Turtle()
sack.hideturtle()
sack.color("aqua")
sack.penup()
sack.setposition(450, 78)
sack.pendown()
tree(sack)
main()