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Mathematics 17 Online
maham:

in the xy-plane the graph of the function f with equation f (x)=ax^2-9 passes through the point (-3,3) what is the value of a

Mercury:

if the function passes through the point (-3,3), then we can set f(x) = 3 and x = -3 like so: f (x)=ax^2-9 3 = a(-3)^2 - 9 from there, solve for a. be careful with the sign on (-3)^2

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