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The following table shows a direct variation. 3 15 18 27 y 5 6 9 Find y . 0 1 2 3
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a direct variation takes the form y = kx , where x is the input value, y is the output, and k is a constant so, you can take any of the x,y values in the table (except the first one) and plug them in for k for example, the second column, x = 15, and y = 3 so plug in x = 15, and y = 3 into y = kx and solve for x then, going back to the first column, plug in your x and k value into y = kx and solve for y please tell me if anything is confusing or you want to check your solution
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