Question

when a cyclist swueezes her brake lever, she can stop with an acceleration of -3.0m/s^2. how far will her bike travel while coming to a complete stop if her intital speed 11m/s

Answer 1

you can use the kinematic equation

\[(v_f)^{2}=(v_0)^{2}+2a \Delta(x)\]where vf = final velocity = 0, since the cyclist is stopping
v0 = 11 m/s
a = -3.0 m/s^2
and x is the stopping distance, which you're solving for

plug in the appropriate quantites and solve for x.